-25x^2=-10x-8

Solution for -25x^2=-10x-8 equation:

-25x^2=-10x-8

We move all terms to the left:

-25x^2-(-10x-8)=0

We get rid of parentheses

-25x^2+10x+8=0

a = -25; b = 10; c = +8;
Δ = b2-4ac
Δ = 102-4·(-25)·8
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-30}{2*-25}=\frac{-40}{-50}
=4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+30}{2*-25}=\frac{20}{-50}
=-2/5
$